Distance from North Dakota to Seymour
Distance from North Dakota to Seymour is 1,550 kilometers. This air travel distance is equal to 963 miles.
The air travel (bird fly) shortest distance between North Dakota and Seymour is 1,550 km= 963 miles.
If you travel with an airplane (which has average speed of 560 miles) from North Dakota to Seymour, It takes 1.72 hours to arrive.
North Dakota
North Dakota is located in United States.
| GPS Coordinates (DMS) | 47° 33´ 5.3640'' N 101° 0´ 7.2360'' W |
|---|---|
| Latitude | 47.55149 |
| Longitude | -101.00201 |
| Altitude | 567 m |
| Country | United States |
North Dakota Distances to Cities
| North Dakota | Distance |
|---|---|
| Distance from North Dakota to Pennsylvania | 2,014 km |
| Distance from North Dakota to South Dakota | 407 km |
| Distance from North Dakota to Washington | 2,159 km |
| Distance from North Dakota to Virginia | 2,142 km |
| Distance from North Dakota to Oregon | 1,574 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |