Distance from North Dakota to San Benito
Distance from North Dakota to San Benito is 2,395 kilometers. This air travel distance is equal to 1,488 miles.
The air travel (bird fly) shortest distance between North Dakota and San Benito is 2,395 km= 1,488 miles.
If you travel with an airplane (which has average speed of 560 miles) from North Dakota to San Benito, It takes 2.66 hours to arrive.
North Dakota
North Dakota is located in United States.
| GPS Coordinates (DMS) | 47° 33´ 5.3640'' N 101° 0´ 7.2360'' W |
|---|---|
| Latitude | 47.55149 |
| Longitude | -101.00201 |
| Altitude | 567 m |
| Country | United States |
North Dakota Distances to Cities
| North Dakota | Distance |
|---|---|
| Distance from North Dakota to Pennsylvania | 2,014 km |
| Distance from North Dakota to South Dakota | 407 km |
| Distance from North Dakota to Washington | 2,159 km |
| Distance from North Dakota to Virginia | 2,142 km |
| Distance from North Dakota to Oregon | 1,574 km |
San Benito
San Benito is located in United States.
| GPS Coordinates | 26° 7´ 57.2880'' N 97° 37´ 51.9600'' W |
|---|---|
| Latitude | 26.13258 |
| Longitude | -97.63110 |
| Altitude | 16 m |
| Country | United States |
San Benito Distances to Cities
| San Benito | Distance |
|---|---|
| Distance from San Benito to Weslaco | 36 km |
| Distance from San Benito to Phoenix | 1,612 km |
| Distance from San Benito to Bellevue Wa | 3,210 km |
| Distance from San Benito to Bel Air North | 2,474 km |
| Distance from San Benito to Arlington Heights | 1,978 km |