Distance from Lins to Secaucus
Distance from Lins to Secaucus is 7,359 kilometers. This air travel distance is equal to 4,573 miles.
The air travel (bird fly) shortest distance between Lins and Secaucus is 7,359 km= 4,573 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lins to Secaucus, It takes 8.17 hours to arrive.
Lins
Lins is located in Brazil.
| GPS Coordinates (DMS) | 21° 40´ 42.9960'' S 49° 44´ 33.0000'' W |
|---|---|
| Latitude | -21.67861 |
| Longitude | -49.74250 |
| Altitude | 411 m |
| Country | Brazil |
Lins Distances to Cities
| Lins | Distance |
|---|---|
| Distance from Lins to Shreveport | 7,609 km |
| Distance from Lins to Edison | 7,345 km |
| Distance from Lins to Colonial Heights | 7,141 km |
| Distance from Lins to Rahway | 7,349 km |
| Distance from Lins to Jefferson | 7,287 km |
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |