Distance from Jefferson City to Sioux Falls
Distance from Jefferson City to Sioux Falls is 670 kilometers. This air travel distance is equal to 416 miles.
The air travel (bird fly) shortest distance between Jefferson City and Sioux Falls is 670 km= 416 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Sioux Falls, It takes 0.74 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Sioux Falls
Sioux Falls is located in United States.
| GPS Coordinates | 43° 32´ 59.8920'' N 96° 42´ 1.1880'' W |
|---|---|
| Latitude | 43.54997 |
| Longitude | -96.70033 |
| Altitude | 449 m |
| Country | United States |
Sioux Falls Distances to Cities
| Sioux Falls | Distance |
|---|---|
| Distance from Sioux Falls to Rapid City | 529 km |
| Distance from Sioux Falls to La Crosse | 441 km |
| Distance from Sioux Falls to Onalaska | 442 km |
| Distance from Sioux Falls to Sheboygan | 725 km |
| Distance from Sioux Falls to Wausau | 586 km |