Distance from Jefferson City to Sapulpa
Distance from Jefferson City to Sapulpa is 452 kilometers. This air travel distance is equal to 281 miles.
The air travel (bird fly) shortest distance between Jefferson City and Sapulpa is 452 km= 281 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Sapulpa, It takes 0.5 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Sapulpa
Sapulpa is located in United States.
| GPS Coordinates | 35° 59´ 55.3200'' N 96° 6´ 51.0120'' W |
|---|---|
| Latitude | 35.99870 |
| Longitude | -96.11417 |
| Altitude | 223 m |
| Country | United States |
Sapulpa Distances to Cities
| Sapulpa | Distance |
|---|---|
| Distance from Sapulpa to Little Elm | 324 km |
| Distance from Sapulpa to Yukon | 159 km |
| Distance from Sapulpa to Memphis | 558 km |
| Distance from Sapulpa to Colorado Springs | 832 km |
| Distance from Sapulpa to Amarillo | 525 km |