Distance from Jefferson City to Dinuba
Distance from Jefferson City to Dinuba is 2,406 kilometers. This air travel distance is equal to 1,495 miles.
The air travel (bird fly) shortest distance between Jefferson City and Dinuba is 2,406 km= 1,495 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Dinuba, It takes 2.67 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Dinuba
Dinuba is located in United States.
| GPS Coordinates | 36° 32´ 35.8080'' N 119° 23´ 13.4520'' W |
|---|---|
| Latitude | 36.54328 |
| Longitude | -119.38707 |
| Altitude | 105 m |
| Country | United States |