Distance from Jacksonville Beach to Jefferson City
Distance from Jacksonville Beach to Jefferson City is 1,349 kilometers. This air travel distance is equal to 838 miles.
The air travel (bird fly) shortest distance between Jacksonville Beach and Jefferson City is 1,349 km= 838 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jacksonville Beach to Jefferson City, It takes 1.5 hours to arrive.
Jacksonville Beach
Jacksonville Beach is located in United States.
| GPS Coordinates (DMS) | 30° 17´ 40.8840'' N 81° 23´ 35.3040'' W |
|---|---|
| Latitude | 30.29469 |
| Longitude | -81.39314 |
| Altitude | 3 m |
| Country | United States |
Jacksonville Beach Distances to Cities
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |