Distance from Clayton to Faribault
Distance from Clayton to Faribault is 674 kilometers. This air travel distance is equal to 419 miles.
The air travel (bird fly) shortest distance between Clayton and Faribault is 674 km= 419 miles.
If you travel with an airplane (which has average speed of 560 miles) from Clayton to Faribault, It takes 0.75 hours to arrive.
Clayton
Clayton is located in United States.
| GPS Coordinates (DMS) | 38° 38´ 33.1800'' N 90° 19´ 25.4280'' W |
|---|---|
| Latitude | 38.64255 |
| Longitude | -90.32373 |
| Altitude | 175 m |
| Country | United States |
Clayton Distances to Cities
| Clayton | Distance |
|---|---|
| Distance from Clayton Mo to Charleston Wv | 759 km |
| Distance from Clayton Mo to Merced | 2,642 km |
| Distance from Clayton Mo to Flagstaff | 1,934 km |
| Distance from Clayton Mo to Des Moines Ia | 432 km |
| Distance from Clayton Mo to San Jose | 2,763 km |
Faribault
Faribault is located in United States.
| GPS Coordinates | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |