Distance from Arayat to Rubidoux
Distance from Arayat to Rubidoux is 11,805 kilometers. This air travel distance is equal to 7,335 miles.
The air travel (bird fly) shortest distance between Arayat and Rubidoux is 11,805 km= 7,335 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arayat to Rubidoux, It takes 13.1 hours to arrive.
Arayat
Arayat is located in Philippines.
| GPS Coordinates (DMS) | 15° 9´ 1.8000'' N 120° 46´ 10.9200'' E |
|---|---|
| Latitude | 15.15050 |
| Longitude | 120.76970 |
| Altitude | 14 m |
| Country | Philippines |
Arayat Distances to Cities
| Arayat | Distance |
|---|---|
| Distance from Arayat to Brook Park | 13,329 km |
| Distance from Arayat to Metairie | 14,018 km |
| Distance from Arayat to Montebello | 11,749 km |
| Distance from Arayat to North Platte | 12,456 km |
| Distance from Arayat to Cicero | 13,051 km |
Rubidoux
Rubidoux is located in United States.
| GPS Coordinates | 33° 59´ 46.0680'' N 117° 24´ 20.1600'' W |
|---|---|
| Latitude | 33.99613 |
| Longitude | -117.40560 |
| Altitude | 236 m |
| Country | United States |