Distance from Vera Cruz to Christiansburg
Distance from Vera Cruz to Christiansburg is 6,878 kilometers. This air travel distance is equal to 4,274 miles.
The air travel (bird fly) shortest distance between Vera Cruz and Christiansburg is 6,878 km= 4,274 miles.
If you travel with an airplane (which has average speed of 560 miles) from Vera Cruz to Christiansburg, It takes 7.63 hours to arrive.
Vera Cruz
Vera Cruz is located in Brazil.
| GPS Coordinates (DMS) | 12° 37´ 59.9880'' S 41° 1´ 59.9880'' W |
|---|---|
| Latitude | -12.63333 |
| Longitude | -41.03333 |
| Altitude | 533 m |
| Country | Brazil |
Vera Cruz Distances to Cities
| Vera Cruz | Distance |
|---|---|
| Distance from Vera Cruz to Sylvania | 7,438 km |
| Distance from Vera Cruz to Christiansburg | 6,878 km |
| Distance from Vera Cruz to Oak Harbor | 10,437 km |
| Distance from Vera Cruz to San Bruno | 10,116 km |
| Distance from Vera Cruz to Staunton | 6,878 km |
Christiansburg
Christiansburg is located in United States.
| GPS Coordinates | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
|---|---|
| Latitude | 37.12985 |
| Longitude | -80.40894 |
| Altitude | 637 m |
| Country | United States |