Distance from Upper Takutu-Upper Essequibo to New Amsterdam
Distance from Upper Takutu-Upper Essequibo to New Amsterdam is 392 kilometers. This air travel distance is equal to 244 miles.
The air travel (bird fly) shortest distance between Upper Takutu-Upper Essequibo and New Amsterdam is 392 km or 244 miles.
If you travel with an airplane (which has average speed of 560 miles) from Upper Takutu-Upper Essequibo to New Amsterdam, It takes 0.43 hours to arrive.
Upper Takutu-Upper Essequibo
Upper Takutu-Upper Essequibo is located in Guyana.
| GPS Coordinates (DMS) | 2° 55´ 26.2560'' N 58° 44´ 14.4960'' W |
|---|---|
| Latitude | 2.92396 |
| Longitude | -58.73736 |
| Altitude | 385 m |
| Country | Guyana |
Upper Takutu-Upper Essequibo Distances to Cities
New Amsterdam
New Amsterdam is located in Guyana.
| GPS Coordinates | 6° 14´ 52.5480'' N 57° 31´ 1.5600'' W |
|---|---|
| Latitude | 6.24793 |
| Longitude | -57.51710 |
| Altitude | 7 m |
| Country | Guyana |
New Amsterdam Distances to Cities
| New Amsterdam | Distance |
|---|---|
| Distance from New Amsterdam to Georgetown | 94 km |
| Distance from New Amsterdam to Linden | 91 km |
| Distance from New Amsterdam to New Amsterdam | 0 km |