Distance from Tecamac de Felipe Villanueva to Oaxaca de Juarez
Distance from Tecamac de Felipe Villanueva to Oaxaca de Juárez is 377 kilometers. This air travel distance is equal to 234 miles.
The air travel (bird fly) shortest distance between Tecamac de Felipe Villanueva and Oaxaca de Juárez is 377 km= 234 miles.
If you travel with an airplane (which has average speed of 560 miles) from Tecamac de Felipe Villanueva to Oaxaca de Juarez, It takes 0.42 hours to arrive.
Tecamac de Felipe Villanueva
Tecamac de Felipe Villanueva is located in Mexico.
| GPS Coordinates (DMS) | 19° 42´ 46.3680'' N 98° 58´ 8.2200'' W |
|---|---|
| Latitude | 19.71288 |
| Longitude | -98.96895 |
| Altitude | 2279 m |
| Country | Mexico |
Tecamac de Felipe Villanueva Distances to Cities
Oaxaca de Juarez
Oaxaca de Juarez is located in Mexico.
| GPS Coordinates | 17° 3´ 55.5120'' N 96° 43´ 25.1400'' W |
|---|---|
| Latitude | 17.06542 |
| Longitude | -96.72365 |
| Altitude | 1579 m |
| Country | Mexico |