Distance from Sinaloa to Oaxaca de Juarez
Distance from Sinaloa to Oaxaca de Juárez is 1,432 kilometers. This air travel distance is equal to 890 miles.
The air travel (bird fly) shortest distance between Sinaloa and Oaxaca de Juárez is 1,432 km= 890 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sinaloa to Oaxaca de Juarez, It takes 1.59 hours to arrive.
Sinaloa is located in Mexico.
|GPS Coordinates (DMS)||25° 10´ 19.5960'' N |
107° 28´ 46.2720'' W
Map of Sinaloa
Sinaloa Distances to Cities
|Distance from Sinaloa to Michoacan||859 km|
|Distance from Sinaloa to Guadalajara||652 km|
|Distance from Sinaloa to Nayarit||465 km|
|Distance from Sinaloa to Puerto Vallarta||555 km|
|Distance from Sinaloa to Chihuahua||408 km|
Oaxaca de Juarez
Oaxaca de Juarez is located in Mexico.
|GPS Coordinates||17° 3´ 55.5120'' N |
96° 43´ 25.1400'' W