Distance from Saxony-Anhalt to Bad Oeynhausen
Distance from Saxony-Anhalt to Bad Oeynhausen is 200 kilometers. This air travel distance is equal to 124 miles.
The air travel (bird fly) shortest distance between Saxony-Anhalt and Bad Oeynhausen is 200 km= 124 miles.
If you travel with an airplane (which has average speed of 560 miles) from Saxony-Anhalt to Bad Oeynhausen, It takes 0.22 hours to arrive.
Saxony-Anhalt
Saxony-Anhalt is located in Germany.
| GPS Coordinates (DMS) | 51° 57´ 0.9360'' N 11° 41´ 32.1720'' E |
|---|---|
| Latitude | 51.95026 |
| Longitude | 11.69227 |
| Altitude | 76 m |
| Country | Germany |
Saxony-Anhalt Distances to Cities
| Saxony-Anhalt | Distance |
|---|---|
| Distance from Saxony Anhalt to Berlin | 133 km |
| Distance from Saxony Anhalt to North Rhine Westphalia | 285 km |
| Distance from Saxony Anhalt to Hamburg | 212 km |
| Distance from Saxony Anhalt to Bremen | 233 km |
| Distance from Saxony Anhalt to Munich | 424 km |
Bad Oeynhausen
Bad Oeynhausen is located in Germany.
| GPS Coordinates | 52° 12´ 25.1640'' N 8° 48´ 13.1400'' E |
|---|---|
| Latitude | 52.20699 |
| Longitude | 8.80365 |
| Altitude | 58 m |
| Country | Germany |