Distance from San Luis Potosi to Tizayuca
Distance from San Luis Potosí to Tizayuca is 331 kilometers. This air travel distance is equal to 206 miles.
The air travel (bird fly) shortest distance between San Luis Potosí and Tizayuca is 331 km or 206 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Luis Potosi to Tizayuca, It takes 0.37 hours to arrive.
San Luis Potosi
San Luis Potosi is located in Mexico.
| GPS Coordinates (DMS) | 22° 9´ 23.2920'' N 100° 59´ 7.9440'' W |
|---|---|
| Latitude | 22.15647 |
| Longitude | -100.98554 |
| Altitude | 1874 m |
| Country | Mexico |
San Luis Potosí Distances to Cities
Tizayuca
Tizayuca is located in Mexico.
| GPS Coordinates | 19° 50´ 13.9560'' N 98° 58´ 33.8520'' W |
|---|---|
| Latitude | 19.83721 |
| Longitude | -98.97607 |
| Altitude | 2275 m |
| Country | Mexico |