Distance from San Fernando to Oaxaca de Juarez
Distance from San Fernando to Oaxaca de Juárez is 874 kilometers. This air travel distance is equal to 543 miles.
The air travel (bird fly) shortest distance between San Fernando and Oaxaca de Juárez is 874 km or 543 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Fernando to Oaxaca de Juarez, It takes 0.97 hours to arrive.
San Fernando
San Fernando is located in Mexico.
| GPS Coordinates (DMS) | 24° 50´ 50.9640'' N 98° 8´ 53.8080'' W |
|---|---|
| Latitude | 24.84749 |
| Longitude | -98.14828 |
| Altitude | 44 m |
| Country | Mexico |
San Fernando Distances to Cities
| San Fernando | Distance |
|---|---|
| Distance from San Fernando to Tijuana | 2,025 km |
| Distance from San Fernando to Victor Rosales | 509 km |
| Distance from San Fernando to Matamoros | 518 km |
| Distance from San Fernando to Monterrey | 237 km |
| Distance from San Fernando to Ojo De Agua | 579 km |
Oaxaca de Juarez
Oaxaca de Juarez is located in Mexico.
| GPS Coordinates | 17° 3´ 55.5120'' N 96° 43´ 25.1400'' W |
|---|---|
| Latitude | 17.06542 |
| Longitude | -96.72365 |
| Altitude | 1579 m |
| Country | Mexico |