Distance from San Fernando to Manibaug Pasig
Distance from San Fernando to Manibaug Pasig is 170 kilometers. This air travel distance is equal to 106 miles.
The air travel (bird fly) shortest distance between San Fernando and Manibaug Pasig is 170 km or 106 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Fernando to Manibaug Pasig, It takes 0.19 hours to arrive.
San Fernando
San Fernando is located in Philippines.
| GPS Coordinates (DMS) | 16° 36´ 57.2760'' N 120° 18´ 59.8680'' E |
|---|---|
| Latitude | 16.61591 |
| Longitude | 120.31663 |
| Altitude | 9 m |
| Country | Philippines |
San Fernando Distances to Cities
Manibaug Pasig
Manibaug Pasig is located in Philippines.
| GPS Coordinates | 15° 5´ 46.3560'' N 120° 33´ 52.0200'' E |
|---|---|
| Latitude | 15.09621 |
| Longitude | 120.56445 |
| Altitude | 91 m |
| Country | Philippines |
Manibaug Pasig Distances to Cities
| Manibaug Pasig | Distance |
|---|---|
| Distance from Manibaug Pasig to Cebu City | 640 km |
| Distance from Manibaug Pasig to Balayan | 130 km |
| Distance from Manibaug Pasig to Lipa City | 143 km |
| Distance from Manibaug Pasig to Cavite City | 77 km |
| Distance from Manibaug Pasig to Calauan | 133 km |