Distance from Oaxaca de Juarez to Tecamac de Felipe Villanueva
Distance from Oaxaca de Juárez to Tecámac de Felipe Villanueva is 377 kilometers. This air travel distance is equal to 234 miles.
The air travel (bird fly) shortest distance between Oaxaca de Juárez and Tecámac de Felipe Villanueva is 377 km or 234 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oaxaca de Juarez to Tecamac de Felipe Villanueva, It takes 0.42 hours to arrive.
Oaxaca de Juarez
Oaxaca de Juarez is located in Mexico.
| GPS Coordinates (DMS) | 17° 3´ 55.5120'' N 96° 43´ 25.1400'' W |
|---|---|
| Latitude | 17.06542 |
| Longitude | -96.72365 |
| Altitude | 1579 m |
| Country | Mexico |
Oaxaca de Juárez Distances to Cities
Tecamac de Felipe Villanueva
Tecamac de Felipe Villanueva is located in Mexico.
| GPS Coordinates | 19° 42´ 47.0160'' N 98° 58´ 5.9880'' W |
|---|---|
| Latitude | 19.71306 |
| Longitude | -98.96833 |
| Altitude | 2274 m |
| Country | Mexico |
Tecámac de Felipe Villanueva Distances to Cities
| Tecámac de Felipe Villanueva | Distance |
|---|---|
| Distance from Tecamac De Felipe Villanueva 15 to Venceremos | 176 km |
| Distance from Tecamac De Felipe Villanueva 15 to Crucecita | 530 km |
| Distance from Tecamac De Felipe Villanueva 15 to Alborada Jaltenco | 12 km |