Distance from Oaxaca de Juarez to Irapuato
Distance from Oaxaca de Juárez to Irapuato is 631 kilometers. This air travel distance is equal to 392 miles.
The air travel (bird fly) shortest distance between Oaxaca de Juárez and Irapuato is 631 km or 392 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oaxaca de Juarez to Irapuato, It takes 0.7 hours to arrive.
Oaxaca de Juarez
Oaxaca de Juarez is located in Mexico.
| GPS Coordinates (DMS) | 17° 3´ 55.5120'' N 96° 43´ 25.1400'' W |
|---|---|
| Latitude | 17.06542 |
| Longitude | -96.72365 |
| Altitude | 1579 m |
| Country | Mexico |
Oaxaca de Juárez Distances to Cities
Irapuato
Irapuato is located in Mexico.
| GPS Coordinates | 20° 40´ 36.3000'' N 101° 21´ 22.6080'' W |
|---|---|
| Latitude | 20.67675 |
| Longitude | -101.35628 |
| Altitude | 1757 m |
| Country | Mexico |