Distance from to

Distance from Asheboro to Petersburg

Distance from Asheboro to Petersburg is 274 kilometers. This air travel distance is equal to 170 miles.

The air travel (bird fly) shortest distance between Asheboro and Petersburg is 274 km= 170 miles.

If you travel with an airplane (which has average speed of 560 miles) from Asheboro to Petersburg, It takes 0.3 hours to arrive.

Asheboro

Asheboro is located in United States.

GPS Coordinates (DMS)35° 42´ 28.4760'' N
79° 48´ 49.1040'' W
Latitude35.70791
Longitude-79.81364
Altitude256 m
CountryUnited States

Map of Asheboro

Asheboro Distances to Cities

AsheboroDistance
Distance from Asheboro to Winston Salem58 km
Distance from Asheboro to Carrboro70 km
Distance from Asheboro to Virginia Beach367 km
Distance from Asheboro to Houston1,597 km
Distance from Asheboro to Lumberton141 km

Petersburg

Petersburg is located in United States.

GPS Coordinates37° 13´ 40.5480'' N
77° 24´ 6.9480'' W
Latitude37.22793
Longitude-77.40193
Altitude22 m
CountryUnited States

Map of Petersburg

Petersburg Distances to Cities

PetersburgDistance
Distance from Petersburg to Virginia Beach133 km
Distance from Petersburg to Beckley340 km
Distance from Petersburg to Staunton179 km
Distance from Petersburg to Roanoke225 km
Distance from Petersburg to Pampa2,117 km