Distance from Arauca to San Jacinto
Distance from Arauca to San Jacinto is 569 kilometers. This air travel distance is equal to 354 miles.
The air travel (bird fly) shortest distance between Arauca and San Jacinto is 569 km= 354 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arauca to San Jacinto, It takes 0.63 hours to arrive.
Arauca
Arauca is located in Colombia.
GPS Coordinates (DMS) | 7° 4´ 45.7320'' N 70° 45´ 30.1680'' W |
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Latitude | 7.07937 |
Longitude | -70.75838 |
Altitude | 129 m |
Country | Colombia |
Arauca Distances to Cities
Arauca | Distance |
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Distance from Arauca to Tame | 127 km |
Distance from Arauca to Bogota | 458 km |
Distance from Arauca to Lorica | 606 km |
Distance from Arauca to Antioquia | 506 km |
Distance from Arauca to Barranquilla | 617 km |
San Jacinto
San Jacinto is located in Colombia.
GPS Coordinates | 9° 49´ 39.6120'' N 75° 7´ 18.1200'' W |
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Latitude | 9.82767 |
Longitude | -75.12170 |
Altitude | 235 m |
Country | Colombia |
San Jacinto Distances to Cities
San Jacinto | Distance |
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Distance from San Jacinto to Fundacion | 128 km |
Distance from San Jacinto to Pasto | 982 km |
Distance from San Jacinto to Aguazul | 588 km |
Distance from San Jacinto to Fresno | 517 km |
Distance from San Jacinto to San Andres | 780 km |