Distance between Šipkovica and Cazin
Distance between Šipkovica and Cazin is 93.6 km. This distance is equal to 58.16 miles, and 50.5 nautical miles.
The distance line on map shows distance from Šipkovica to Cazin between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Šipkovica to Cazin,
It takes 0.1 hours to arrive.
| Šipkovica | 45.8102869 | 15.9003921 |
|---|---|---|
| Cazin | 44.9690446 | 15.9431582 |
| Distance | 93.6 km | 58.16 miles |
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