Distance between Watson's - Admiralty Pacific Place and Shenzhen Bay
Distance between Watson's - Admiralty Pacific Place and Shenzhen Bay is 31.9 km. This distance is equal to 19.82 miles, and 17.21 nautical miles.
The distance line on map shows distance from Watson's - Admiralty Pacific Place to Shenzhen Bay between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Watson's - Admiralty Pacific Place to Shenzhen Bay,
It takes 0.04 hours to arrive.
| Watson's - Admiralty Pacific Place | 22.277722 | 114.16481 |
|---|---|---|
| Shenzhen Bay | 22.5020944 | 113.9714894 |
| Distance | 31.9 km | 19.82 miles |
Related Distances
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