Distance between Villanova and Secaucus
Distance between Villanova and Secaucus is 137.72 km. This distance is equal to 85.57 miles, and 74.31 nautical miles.
The distance line on map shows distance from Villanova to Secaucus between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Villanova to Secaucus,
It takes 0.15 hours to arrive.
| Villanova | 40.0375832 | -75.3491813 |
|---|---|---|
| Secaucus | 40.7895453 | -74.0565298 |
| Distance | 137.72 km | 85.57 miles |
Related Distances
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