Distance between Tskaltubo and Sevan Lake
Distance between Tskaltubo and Sevan Lake is 317.41 km. This distance is equal to 197.23 miles, and 171.27 nautical miles.
The distance line on map shows distance from Tskaltubo to Sevan Lake between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Tskaltubo to Sevan Lake,
It takes 0.35 hours to arrive.
| Tskaltubo | 42.3284986 | 42.6003682 |
|---|---|---|
| Sevan Lake | 40.3449984 | 45.3351942 |
| Distance | 317.41 km | 197.23 miles |
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