Distance between São Sebastião do Caí and Veranópolis
Distance between São Sebastião do Caí and Veranópolis is 73.89 km. This distance is equal to 45.91 miles, and 39.87 nautical miles.
The distance line on map shows distance from São Sebastião do Caí to Veranópolis between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between São Sebastião do Caí to Veranópolis,
It takes 0.08 hours to arrive.
| São Sebastião do Caí | -29.5875726 | -51.3735594 |
|---|---|---|
| Veranópolis | -28.9408405 | -51.5485214 |
| Distance | 73.89 km | 45.91 miles |
Related Distances
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