Distance between São Sebastião do Caí and Nova Petrópolis
Distance between São Sebastião do Caí and Nova Petrópolis is 33.55 km. This distance is equal to 20.85 miles, and 18.11 nautical miles.
The distance line on map shows distance from São Sebastião do Caí to Nova Petrópolis between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between São Sebastião do Caí to Nova Petrópolis,
It takes 0.04 hours to arrive.
São Sebastião do Caí | -29.5875726 | -51.3735594 |
---|---|---|
Nova Petrópolis | -29.3832221 | -51.1184796 |
Distance | 33.55 km | 20.85 miles |
Related Distances
- Distance between São Sebastião do Caí and Soledade (139,58 km.)
- Distance between São Sebastião do Caí and Tramandaí (126,91 km.)
- Distance between Vacaria and São Sebastião do Caí (127,31 km.)
- Distance between São Sebastião do Caí and Cruz Alta (240,77 km.)
- Distance between Tubarão and São Sebastião do Caí (261,59 km.)
- Distance between São Sebastião do Caí and Dom Pedrito (353,06 km.)