Distance between Swain and Sevierville
Distance between Swain and Sevierville is 49.19 km. This distance is equal to 30.57 miles, and 26.54 nautical miles.
The distance line on map shows distance from Swain to Sevierville between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Swain to Sevierville,
It takes 0.05 hours to arrive.
| Swain | 35.4328955 | -83.4643551 |
|---|---|---|
| Sevierville | 35.8681455 | -83.561835 |
| Distance | 49.19 km | 30.57 miles |
Related Distances
- Distance between Swain and Christiana (267,22 km.)
- Distance between Lenoir and Swain (181,95 km.)
- Distance between Swain and Albertville (281,95 km.)
- Distance between Swain and Roth (555,36 km.)
- Distance between Swain and Hayesville (53,66 km.)
- Distance between Swain and Oak Ridge (96,99 km.)