Distance between Shenandoah and Plattsburg
Distance between Shenandoah and Plattsburg is 154.32 km. This distance is equal to 95.89 miles, and 83.27 nautical miles.
The distance line on map shows distance from Shenandoah to Plattsburg between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Shenandoah to Plattsburg,
It takes 0.17 hours to arrive.
| Shenandoah | 40.75877 | -95.375603 |
|---|---|---|
| Plattsburg | 39.5655549 | -94.4480059 |
| Distance | 154.32 km | 95.89 miles |
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