Distance between Shawinigan and Lac Repris
Distance between Shawinigan and Lac Repris is 370.9 km. This distance is equal to 230.47 miles, and 200.14 nautical miles.
The distance line on map shows distance from Shawinigan to Lac Repris between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Shawinigan to Lac Repris,
It takes 0.41 hours to arrive.
| Shawinigan | 46.55 | -72.7333333 |
|---|---|---|
| Lac Repris | 47.4096803 | -77.4583466 |
| Distance | 370.9 km | 230.47 miles |
Related Distances
- Distance between Shawinigan and The Face (230,67 km.)
- Distance between Shawinigan and Sorel (63,46 km.)
- Distance between Shawinigan and Impasse Hamel (164,01 km.)
- Distance between Shawinigan and Magog (149,91 km.)
- Distance between Shawinigan and Time Square Road (289,24 km.)
- Distance between Shawinigan and Embassy of Serbia (259,37 km.)