Distance between Seymour and Washington Court
Distance between Seymour and Washington Court is 382.03 km. This distance is equal to 237.38 miles, and 206.14 nautical miles.
The distance line on map shows distance from Seymour to Washington Court between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Seymour to Washington Court,
It takes 0.42 hours to arrive.
| Seymour | 38.9592201 | -85.8902547 |
|---|---|---|
| Washington Court | 38.6531313 | -90.2821699 |
| Distance | 382.03 km | 237.38 miles |
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