Distance between Seymour and Jeffersonville
Distance between Seymour and Jeffersonville is 76.95 km. This distance is equal to 47.81 miles, and 41.52 nautical miles.
The distance line on map shows distance from Seymour to Jeffersonville between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Seymour to Jeffersonville,
It takes 0.09 hours to arrive.
| Seymour | 38.9592201 | -85.8902547 |
|---|---|---|
| Jeffersonville | 38.2775702 | -85.7371847 |
| Distance | 76.95 km | 47.81 miles |
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