Distance between Seymour and Clarksburg
Distance between Seymour and Clarksburg is 479.65 km. This distance is equal to 298.04 miles, and 258.82 nautical miles.
The distance line on map shows distance from Seymour to Clarksburg between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Seymour to Clarksburg,
It takes 0.53 hours to arrive.
| Seymour | 38.9592201 | -85.8902547 |
|---|---|---|
| Clarksburg | 39.2806451 | -80.3445341 |
| Distance | 479.65 km | 298.04 miles |
Related Distances
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