Distance between Seymour and Clarksburg
Distance between Seymour and Clarksburg is 479.65 km. This distance is equal to 298.04 miles, and 258.82 nautical miles.
The distance line on map shows distance from Seymour to Clarksburg between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Seymour to Clarksburg,
It takes 0.53 hours to arrive.
| Seymour | 38.9592201 | -85.8902547 |
|---|---|---|
| Clarksburg | 39.2806451 | -80.3445341 |
| Distance | 479.65 km | 298.04 miles |
Related Distances
- Distance between Seymour and East St. Louis (369,21 km.)
- Distance between Westerville and Seymour (285,11 km.)
- Distance between Huntington and Seymour (304,94 km.)
- Distance between Seymour and North Canton (437,98 km.)
- Distance between Seymour and New Brighton (515,35 km.)
- Distance between Seymour and Affton (387,87 km.)