Distance between Seymour and 1018
Distance between Seymour and 1018 is 463.54 km. This distance is equal to 288.03 miles, and 250.12 nautical miles.
The distance line on map shows distance from Seymour to 1018 between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Seymour to 1018,
It takes 0.51 hours to arrive.
| Seymour | 38.9592201 | -85.8902547 |
|---|---|---|
| 1018 | 40.9223962 | -81.0921773 |
| Distance | 463.54 km | 288.03 miles |
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