Distance between Sevierville and Roth
Distance between Sevierville and Roth is 531.34 km. This distance is equal to 330.16 miles, and 286.71 nautical miles.
The distance line on map shows distance from Sevierville to Roth between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevierville to Roth,
It takes 0.59 hours to arrive.
| Sevierville | 35.8681455 | -83.561835 |
|---|---|---|
| Roth | 37.097691 | -89.306206 |
| Distance | 531.34 km | 330.16 miles |
Related Distances
- Distance between Sevierville and Winston-Salem (299,59 km.)
- Distance between Sandy Springs and Sevierville (228,61 km.)
- Distance between Sevierville and Yadkinville (262,74 km.)
- Distance between Sevierville and Color Drive (179,15 km.)
- Distance between Nashville and Sevierville (291,70 km.)
- Distance between Raleigh and Sevierville (443,95 km.)