Distance between Sevierville and Farragut
Distance between Sevierville and Farragut is 54.91 km. This distance is equal to 34.12 miles, and 29.63 nautical miles.
The distance line on map shows distance from Sevierville to Farragut between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevierville to Farragut,
It takes 0.06 hours to arrive.
| Sevierville | 35.8681455 | -83.561835 |
|---|---|---|
| Farragut | 35.8778548 | -84.1711345 |
| Distance | 54.91 km | 34.12 miles |
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