Distance between Sevastopol and Yablonovsky, Republic of Adygea
Distance between Sevastopol and Yablonovsky, Republic of Adygea is 429.84 km. This distance is equal to 267.09 miles, and 231.94 nautical miles.
The distance line on map shows distance from Sevastopol to Yablonovsky, Republic of Adygea between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevastopol to Yablonovsky, Republic of Adygea,
It takes 0.48 hours to arrive.
| Sevastopol | 44.61665 | 33.525367 |
|---|---|---|
| Yablonovsky, Republic of Adygea | 44.983333 | 38.95 |
| Distance | 429.84 km | 267.09 miles |
Related Distances
- Distance between Sevastopol and Gelendzhik (359,34 km.)
- Distance between Sevastopol and Kamchatka (324,96 km.)
- Distance between Comrat and Sevastopol (422,93 km.)
- Distance between Sevastopol and Yelizavétinskaya (418,32 km.)
- Distance between Afipsky and Sevastopol (420,19 km.)
- Distance between Bryukhovetskaya and Sevastopol (448,84 km.)