Distance between Sevastopol and Djankoj
Distance between Sevastopol and Djankoj is 139.04 km. This distance is equal to 86.4 miles, and 75.03 nautical miles.
The distance line on map shows distance from Sevastopol to Djankoj between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevastopol to Djankoj,
It takes 0.15 hours to arrive.
| Sevastopol | 44.61665 | 33.525367 |
|---|---|---|
| Djankoj | 45.7094038 | 34.3877402 |
| Distance | 139.04 km | 86.4 miles |
Related Distances
- Distance between Reni and Sevastopol (422,11 km.)
- Distance between Sevastopol and Yablonovsky (429,84 km.)
- Distance between Saky and Sevastopol (57,28 km.)
- Distance between Sevastopol and Krasnoperekops'k (149,99 km.)
- Distance between Novotitarovskaya and Sevastopol (436,11 km.)