Distance between Sevan Lake and Haji Zeynalabdin Taghiyev Street
Distance between Sevan Lake and Haji Zeynalabdin Taghiyev Street is 381.61 km. This distance is equal to 237.12 miles, and 205.92 nautical miles.
The distance line on map shows distance from Sevan Lake to Haji Zeynalabdin Taghiyev Street between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sevan Lake to Haji Zeynalabdin Taghiyev Street,
It takes 0.42 hours to arrive.
| Sevan Lake | 40.3449984 | 45.3351942 |
|---|---|---|
| Haji Zeynalabdin Taghiyev Street | 40.3696477 | 49.8394907 |
| Distance | 381.61 km | 237.12 miles |
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