Distance between Serpukhov and Alexandrov, Vladimir Oblast
Distance between Serpukhov and Alexandrov, Vladimir Oblast is 183.02 km. This distance is equal to 113.73 miles, and 98.76 nautical miles.
The distance line on map shows distance from Serpukhov to Alexandrov, Vladimir Oblast between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Serpukhov to Alexandrov, Vladimir Oblast,
It takes 0.2 hours to arrive.
| Serpukhov | 54.9179562 | 37.4229963 |
|---|---|---|
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
| Distance | 183.02 km | 113.73 miles |
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