Distance from Seelze to Osterholz-Scharmbeck
Distance from Seelze to Osterholz-Scharmbeck is 107 kilometers. This air travel distance is equal to 66 miles.
The air travel (bird fly) shortest distance between Seelze and Osterholz-Scharmbeck is 107 km or 66 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seelze to Osterholz-Scharmbeck, It takes 0.12 hours to arrive.
Seelze
Seelze is located in Germany.
| GPS Coordinates (DMS) | 52° 23´ 46.8600'' N 9° 35´ 50.1720'' E |
|---|---|
| Latitude | 52.39635 |
| Longitude | 9.59727 |
| Altitude | 50 m |
| Country | Germany |
Seelze Distances to Cities
| Seelze | Distance |
|---|---|
| Distance from Seelze to Hannover | 10 km |
| Distance from Seelze to Heide | 203 km |
| Distance from Seelze to Rheine | 148 km |
| Distance from Seelze to Goch | 249 km |
| Distance from Seelze to Aurich | 186 km |
Osterholz-Scharmbeck
Osterholz-Scharmbeck is located in Germany.
| GPS Coordinates | 53° 13´ 37.1280'' N 8° 47´ 43.0080'' E |
|---|---|
| Latitude | 53.22698 |
| Longitude | 8.79528 |
| Altitude | 25 m |
| Country | Germany |