Distance between Seaford and Villanova
Distance between Seaford and Villanova is 172.47 km. This distance is equal to 107.17 miles, and 93.07 nautical miles.
The distance line on map shows distance from Seaford to Villanova between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Seaford to Villanova,
It takes 0.19 hours to arrive.
| Seaford | 40.6659344 | -73.4881809 |
|---|---|---|
| Villanova | 40.0375832 | -75.3491813 |
| Distance | 172.47 km | 107.17 miles |
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