Distance between Sayreville and Villanova
Distance between Sayreville and Villanova is 96.1 km. This distance is equal to 59.71 miles, and 51.85 nautical miles.
The distance line on map shows distance from Sayreville to Villanova between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sayreville to Villanova,
It takes 0.11 hours to arrive.
| Sayreville | 40.4594021 | -74.360846 |
|---|---|---|
| Villanova | 40.0375832 | -75.3491813 |
| Distance | 96.1 km | 59.71 miles |
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