Distance between Savage and Warrenton
Distance between Savage and Warrenton is 96.62 km. This distance is equal to 60.04 miles, and 52.14 nautical miles.
The distance line on map shows distance from Savage to Warrenton between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Savage to Warrenton,
It takes 0.11 hours to arrive.
| Savage | 39.1436111 | -76.8247222 |
|---|---|---|
| Warrenton | 38.7134516 | -77.7952712 |
| Distance | 96.62 km | 60.04 miles |
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- Distance between Savage and Warrenton (96,62 km.)