Distance between Savage and Villanova
Distance between Savage and Villanova is 160.82 km. This distance is equal to 99.93 miles, and 86.78 nautical miles.
The distance line on map shows distance from Savage to Villanova between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Savage to Villanova,
It takes 0.18 hours to arrive.
| Savage | 39.1436111 | -76.8247222 |
|---|---|---|
| Villanova | 40.0375832 | -75.3491813 |
| Distance | 160.82 km | 99.93 miles |
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