Distance between Sanford and Jacksonville Beach
Distance between Sanford and Jacksonville Beach is 169.88 km. This distance is equal to 105.56 miles, and 91.67 nautical miles.
The distance line on map shows distance from Sanford to Jacksonville Beach between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Sanford to Jacksonville Beach,
It takes 0.19 hours to arrive.
| Sanford | 28.7588218 | -81.2941794 |
|---|---|---|
| Jacksonville Beach | 30.2841224 | -81.3961338 |
| Distance | 169.88 km | 105.56 miles |
Related Distances
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