Distance between Russellville and Searcy Airport
Distance between Russellville and Searcy Airport is 373.74 km. This distance is equal to 232.23 miles, and 201.67 nautical miles.
The distance line on map shows distance from Russellville to Searcy Airport between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Russellville to Searcy Airport,
It takes 0.41 hours to arrive.
Russellville | 34.5078726 | -87.7286431 |
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Searcy Airport | 35.214949 | -91.7337546 |
Distance | 373.74 km | 232.23 miles |
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