Distance between Pereslavl-Zalessky and Alexandrov, Vladimir Oblast
Distance between Pereslavl-Zalessky and Alexandrov, Vladimir Oblast is 38.59 km. This distance is equal to 23.98 miles, and 20.82 nautical miles.
The distance line on map shows distance from Pereslavl-Zalessky to Alexandrov, Vladimir Oblast between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Pereslavl-Zalessky to Alexandrov, Vladimir Oblast,
It takes 0.04 hours to arrive.
| Pereslavl-Zalessky | 56.7333333 | 38.85 |
|---|---|---|
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
| Distance | 38.59 km | 23.98 miles |
Related Distances
- Distance between Pereslavl-Zalessky and Gus-Khrustalny District (188,13 km.)
- Distance between Pereslavl-Zalessky and Volokolamsk (194,73 km.)
- Distance between Pereslavl-Zalessky and Zheleznodorozhny (120,85 km.)
- Distance between Pereslavl-Zalessky and Rodniki (179,67 km.)
- Distance between Pereslavl-Zalessky and Balashikha (117,81 km.)
- Distance between Pereslavl-Zalessky and Lyubertsy (131,90 km.)