Distance between Martinsburg and American Winds Flight Academy
Distance between Martinsburg and American Winds Flight Academy is 345.57 km. This distance is equal to 214.72 miles, and 186.47 nautical miles.
The distance line on map shows distance from Martinsburg to American Winds Flight Academy between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Martinsburg to American Winds Flight Academy,
It takes 0.38 hours to arrive.
| Martinsburg | 39.4562099 | -77.9638869 |
|---|---|---|
| American Winds Flight Academy | 41.0399133 | -81.4680383 |
| Distance | 345.57 km | 214.72 miles |
Related Distances
- Distance between East Meadow and Martinsburg (399,91 km.)
- Distance between Martinsburg and East Brunswick (322,16 km.)
- Distance between Martinsburg and Virginia Street West (341,22 km.)
- Distance between Washington D.C. and Martinsburg (101,41 km.)
- Distance between Martinsburg and 10 (362,46 km.)
- Distance between Martinsburg and New Zealand Missions To UN (368,34 km.)