Distance between Martinsburg and American Winds Flight Academy
Distance between Martinsburg and American Winds Flight Academy is 345.57 km. This distance is equal to 214.72 miles, and 186.47 nautical miles.
The distance line on map shows distance from Martinsburg to American Winds Flight Academy between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Martinsburg to American Winds Flight Academy,
It takes 0.38 hours to arrive.
| Martinsburg | 39.4562099 | -77.9638869 |
|---|---|---|
| American Winds Flight Academy | 41.0399133 | -81.4680383 |
| Distance | 345.57 km | 214.72 miles |
Related Distances
- Distance between Martinsburg and United States Capitol (103,63 km.)
- Distance between Martinsburg and AFG Road (191,08 km.)
- Distance between Lyndhurst and Martinsburg (359,49 km.)
- Distance between Middletown and Martinsburg (372,38 km.)
- Distance between Martinsburg and A2Z Driving School, Inc. (87,44 km.)
- Distance between Martinsburg and Brooklyn (368,00 km.)