Distance between Lexington and Seymour
Distance between Lexington and Seymour is 158.08 km. This distance is equal to 98.23 miles, and 85.3 nautical miles.
The distance line on map shows distance from Lexington to Seymour between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Lexington to Seymour,
It takes 0.18 hours to arrive.
| Lexington | 38.0405837 | -84.5037164 |
|---|---|---|
| Seymour | 38.9592201 | -85.8902547 |
| Distance | 158.08 km | 98.23 miles |
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